please tell me how to rework the function so that its output is the opposite. When entering the value -105, it should output (7 5 3), but for me it outputs (3 5 7).
#include <stdio.h>void simpleFactors(unsigned int a, unsigned int last, unsigned int n);void printFactor(unsigned int last, unsigned int n);int main(){ unsigned int a; scanf("%u", &a); simpleFactors(a, 2, 0); printf("\n"); return 0;}void simpleFactors(unsigned int a, unsigned int last, unsigned int n){ if (a % last == 0) { if (a > 1) simpleFactors(a / last, last, n + 1); } else { printFactor(last, n); if (a == 1) return; if (last * last > a) { printf("%ld ", a); return; } simpleFactors(a, last + 1, 0); printf("\n"); }}void printFactor(unsigned int last, unsigned int n){ if (n == 0) return; if (n == 1) printf("%ld ", last); else printf("%ld^%ld ", last, n);}I made some small changes in function. This program should pass some tests. I am interested in the correct output when entering the number 105. I managed to reverse the output, but now the program outputs (7 5), without the third digit.
void simpleFactors(unsigned int a, unsigned int last, unsigned int n){ if (a % last == 0) { if (a > 1) simpleFactors(a / last, last, n+1); } else { if (last > a) { printFactor(last, n); } if (a == 1) return; if (last * last > a) { printf("%ld ", a); printFactor(last, n); return; } simpleFactors(a, last + 1, 0); printf("\n"); }}